10a^2+9a+2=0

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Solution for 10a^2+9a+2=0 equation: 



10a^2+9a+2=0

a = 10; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·10·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*10}=\frac{-10}{20}
=-1/2
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*10}=\frac{-8}{20}
=-2/5
$

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